By Read C. J.
It truly is renowned that the classical series areas co and Ip (1 <= p <) have, as much as equivalence, only one symmetric foundation. nevertheless, there are examplesof Orlicz series areas that have uncountably many jointly nonequivalentsymmetric bases. therefore in , p. a hundred thirty, the query is requested whetherthere is a Banach house with, as much as equivalence, a couple of symmetric basis,but no longer uncountably many. during this paper we solution the query certainly, byexhibiting a Banach house with, as much as equivalence, accurately symmetricbases.
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Extra info for A Banach Space With, Up To Equivalence, Precisely Two Symmetric Bases
E. the regression of Z(V ) on Z(V ) is linear and coincides with the ﬁrst bisector. g. values selected for being rich, being as rich as expected). This is not the case of the estimator Z(V ) taken as the sampled value of Z(V ). Having a variance higher than that of Z(V ) due to the support eﬀect, it is conditionally biased, with E[Z(V )|Z(V ) ] < Z(V ) when Z(V ) is high. g. above a cut-oﬀ z: E[Z(V )|Z(V ) > z] < E[Z(V ) |Z(V ) > z] 26 Jacques Rivoirard Krige’s lognormal estimator aims at correcting this conditional bias.
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