A solution manual to Computer Architecture: A Quantitative by John L. Hennessy & David Patterson

By John L. Hennessy & David Patterson

Show description

Read Online or Download A solution manual to Computer Architecture: A Quantitative Approach 4E (John L. Hennessy & David Patterson) PDF

Best nonfiction_6 books

Wellness and Prevention, An Issue of Primary Care Clinics in Office Practice (The Clinics: Internal Medicine)

This factor covers quite a lot of sufferer matters, together with weightloss, smoking cessation, pressure, sleep difficulties, workout, and use of supplements. additionally incorporated are articles approximately combating middle illness, weight problems, and melanoma.

Additional info for A solution manual to Computer Architecture: A Quantitative Approach 4E (John L. Hennessy & David Patterson)

Sample text

The memory dependence from node 18 of one iteration of the for loop to node 11 of a future iteration is shown as an arc of dependence distance 1. This is conservative since the dependence may not be on the immediate next iteration. This, however, gives the worst-case constraint so that the compiler will constrain its actions to be on the safe side. 26 is simplified in that it does not contain all the dependence arcs. Those dependence arcs that do not impose any further scheduling constraints than the ones shown are omitted for clarity.

This is expressed with a “1” value on the dependence arc to indicate that the dependence goes from one iteration to the next. The memory dependence from node 18 of one iteration of the for loop to node 11 of a future iteration is shown as an arc of dependence distance 1. This is conservative since the dependence may not be on the immediate next iteration. This, however, gives the worst-case constraint so that the compiler will constrain its actions to be on the safe side. 26 is simplified in that it does not contain all the dependence arcs.

P0: read 100 Read miss, satisfied by memory P0: write 108 <-- 48 Write hit, sends invalidate P0: write 130 <-- 78 Write miss, satisfied by memory, write back 110 Implementation 1: 100 + 15 + 10 + 100 = 225 stall cycles Implementation 2: 100 + 15 + 10 + 100 = 225 stall cycles c. P1: read 120 Read miss, satisfied by memory P1: read 128 Read hit P1: read 130 Read miss, satisfied by memory Implementation 1: 100 + 0 + 100 = 200 stall cycles Implementation 2: 100 + 0 + 100 = 200 stall cycles d. 27. 27 Protocol diagram.

Download PDF sample

Rated 4.47 of 5 – based on 10 votes